Question

Least common denominator?

Answer 1

\[ \frac{ 3x }{ x+1 } + \frac{ x+1 }{ 2x } + \frac{ 5 }{ x}\]

Answer 2

you need all the factors that you see
what is your best guess for the common multiple of \(x+1\) , \(2x\) and \(x\) ?

Answer 3

1x?

Answer 4

hold the phone
not "greatest common factor" but rather "least common multiple"
also \(x\) is not a factor of \(x+1\)

Answer 5

Alright, I understand, would you mind helping me, I'm not quite sure

Answer 6

if for example \(x\) was \(10\) then those numbers would be \(10+1,2\times 10, 10\) or
\[11,20,10\] what is the least common multiple of those three numbers?

Answer 7

if it is not clear for those three numbers let me know and i will say it

Answer 8

Sorry, I'm still a little in the unknowing :c I would like your help :)

Answer 9

k no problem

Answer 10

:)

Answer 11

the least common multiple of \(11,20,10\) is \(11\times 20=220\) because all three numbers divide \(220\) evenly

Answer 12

I understand now the least common multiple, but I'm not sure how to apply it to what I have

Answer 13

notice that i only multiplied \(11\times 20\) i don't need an extra \(10\) because \(10\) is already a factor of \(20\)
it is identical with the variables
the least common multiple will be
\[(x+1)\times 2x\]

Answer 14

\(x+1\) is a factor of \(2x(x+1)\) and \(2x\) is a factor of \(2x(x+1)\) and also \(x\) is a factor of \(2x(x+1)\) therefore
\[2x(x+1)\] is the least common multiple, and that will be your denominator if you add or subtract

Answer 15

Wow, so clear now :D THANK YOU omg <333

Answer 16

btw i like "little in the unknowing"
can i use it?

Answer 17

yw

Answer 18

Well absolutely :) Everything is yours if you want it to be c:

Answer 19

thanks

Answer 20

Haha, I'll catch you later I suppose :) Thanks again

Answer 21

later