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Mathematics 20 Online
OpenStudy (anonymous):

Geometry Help please!! I will post the question as an equation

sammixboo (sammixboo):

Tag me when you are done with your equation ;)

OpenStudy (anonymous):

Oh okay thanks!!!!

OpenStudy (anonymous):

30°-60°-90° triangle has a hypotenuse with a length of 10. What is the length of the longer leg of the triangle? A. 5 B. \[5\sqrt3\] C.\[5\sqrt2\] D. 20

OpenStudy (anonymous):

@sammixboo

sammixboo (sammixboo):

Ok, first let's solve B. and C.... Do you know how to solve them?

OpenStudy (anonymous):

Kinda

OpenStudy (anonymous):

not really xD

OpenStudy (anonymous):

to find the sides of a 30°-60°-90° triangle, i usually use this formulas i let \(x\) be the shortest side so since the hypotenuse is twice as long as the shortest side it will be \(2x\) and for the other side it will be \(x \sqrt{3}\) (if you are wondering where i get these, i applied basic trigonometric identities, SOH CAH TOA) now you are given the length of the hypotenuse 10, so from the formula, 10=2x so the shortest side will be x=5 the longer side is \(x\sqrt{3}\), if x=5, the longer side will be?? if you did not understand my method,just let me know, i'll try to explain the other method :)

OpenStudy (anonymous):

No idea what you just said

OpenStudy (anonymous):

alright, let's try method 2 using trig identities. you are looking for A or the longer side \(\Large sin\ \theta = \frac{opposite}{hypotenuse}=sin\ 60°=\frac{A}{10}\) solving for A, you'll get \(\Large A=10sin\ 60°\) |dw:1397877919608:dw|

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