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Mathematics 13 Online
OpenStudy (anonymous):

Find the zeros of the polynomial function: f(x)= x^2(x+3)^2(x-4)(x+1)^4

OpenStudy (anonymous):

set each factor equal do zero and solve for \(x\) for example, if \(x+3=0\) then \(x=-3\)

OpenStudy (fibonaccichick666):

^why would you do that? ^ Keep that question in the back of your mind. What does that do?

OpenStudy (mathmale):

Strong hint: a "zero" of a polynomial is a value of the independent variable (x) that makes the polynomial = 0. Take the given polynomial, f(x)= x^2(x+3)^2(x-4)(x+1)^4, and set the whole thing equal to 0. Then find the several values of x at which the poly. is 0. Those are your "zeros." On second thought: I find it difficult to decipher (make sense of) your polynomial. Where are the (+) and (-) signs between the various terms with different powers of x? Before you do anything else, please go back to the original problem and type the poly here again.

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