Question

how do i solve 17^{1-x}=7

Answer 1

Take the log (any base) of each side, first.

Answer 2

Use the law of logs to "bring down" the (1-x).

Divide by log(17)

Should be pretty straight forward to solve for x from there.

Answer 3

change of base formula
\[\large b^A=B\iff A=\frac{\log(A)}{\log(B)}\]

Answer 4

\[\large 17^{1-x}=7\iff 1-x=\frac{\log(7)}{\log(17)}\] then algebra and a calculator

Answer 5

Sorry, Im still not seeing it. Please explain