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MIT 8.01 Physics I Classical Mechanics, Fall 1999 11 Online
OpenStudy (anonymous):

During lecture 1 @26:16, why is the constant multiplied by square root of h/g proportional to sqrt(h) ? Link to part I'm talking about: https://www.youtube.com/watch?v=PmJV8CHIqFc#t=1576

OpenStudy (vincent-lyon.fr):

t is proportional to √h because neither C nor g depend on h.

OpenStudy (anonymous):

Oh, as in C and g are constant values? is that what it means to be independent of h?

OpenStudy (vincent-lyon.fr):

Not necessarily. These could change with respect to some other quantity. As long as they do not change with h, then you can say that dependence of t with respect to h is a square-root one.

OpenStudy (anonymous):

Many thanks! That makes sense now.

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