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Why is the limit of (1-cos(x+5))/(x+5) as x approaches -5 equal to zero?
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are you familiar with l'hopital's rule?
not yet, I only know that there is a theorem that says that the limit of 1-cosx/x as x approaches 0 is zero. Is that related to this?
yes it is related. just let y=x+5 and you have lim y->0 (1-cosy)/y so back to your theorem this is equal to 0
l'hopital's rule says if you separately differentiate the top and bottom of the original expression and then take the limit, then the final expression is equal to this.
but the limit is as x->-5
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If y = x+5 then lim y->0 of y = lim x ->-5 of x+5
okay , got it thanks :)
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