Urgent help please. :)
I'll give credits..

Question

Urgent help please. :)
I'll give credits..

anonymous · Answer

$$\lim_{u \rightarrow1}\frac{( \sqrt[3]{u+7})-2 }{ 1-u}$$

anonymous · Answer

If you substitute 1 to the expression, the answer will be indeterminate.. (That's 0 over 0).. we need to rationalize the cube root.

sburchette · Answer

Specifically, substituting 1 yields 0/0. That makes this limit valid for using L'Hopital's rule.

anonymous · Answer

Yes.. that's indeterminate.. But a limit of type 0/0 may exist, and to compute the limit, we may use rationalization of expressions..

sburchette · Answer

Have you learned L'Hopital's rule yet? If not, then rationalization may be the best route to take.

anonymous · Answer

Not yet.. but can you help me in rationalizing the equation? :)

sburchette · Answer

Since we have a cube root in the numerator, we could try multiplying the numerator and denominator by $$\sqrt[3]{u+7}$$

anonymous · Answer

@hartnn @ParthKohli 
need help guys.. sorry for the disturbance.. :))