Question

what is the value of csc(-19π/3)? I have no trig. knowledge except for sohcahtoa

Answer 1

Do you know 1/csc is which trigo function?

Answer 2

….not really but is it cos?

Answer 3

The first step is like this: \(\Large\displaystyle\csc\left(\frac{-19\pi}3\right)=\frac1{\sin\left(\frac{-19\pi}3\right)}\)

Answer 4

Remember that cosine is to secant and sine is to cosecant

Answer 5

ok…. question, what is secant and cosecant… sorry

Answer 6

secant is 1/cosine, abbreviated as sec

Answer 7

cosecant is 1/sine, abbreviated as csc or cosec

Answer 8

Get it?

Answer 9

i think so Thanks! :D so after csc(−19π3)=1sin(−19π3) what happens?

Answer 10

Do you know what's the period of sine?

Answer 11

no

Answer 12

Okay, so for any trigonometric function, the period is always 2π, meaning that the function will repeat itself after 2π.

Answer 13

That means that \(\sin x=\sin(2\pi+x)\)

Answer 14

Get it?

Answer 15

i think so

Answer 16

Okay, use the formula above 3 times

Answer 17

it will get easier as i see it more but your doing an amazing job explaining to me and answering by never ending questions… ok

Answer 18

No problem, asking questions is the most effective way of learning

Answer 19

so is it set up like this: csc(−19π3)=1sin(−19π3) X sine(2pi + x) X sine(2pi +x) X sin(2pi +x) ?

Answer 20

Never mind...

Answer 21

\[\Large\displaystyle\csc\left(\frac{-19\pi}3\right)=\frac1{\sin\left(\frac{-19\pi}3\right)}=\frac1{\sin\left(\frac{-19\pi}3+2\pi+2\pi+2\pi\right)}\]

Answer 22

\[\Large=\frac1{\sin\frac{-\pi}3}\]

Answer 23

oh… ok thanks :D

Answer 24

You have the table right

Answer 25

is that all there is to it?

Answer 26

Well you have to find its value using the table

Answer 27

ok thanks you have been a great help!

Answer 28

No problem :)