The population of a local species of flies can be found using an infinite geometric series where a1 = 940 and the common ratio is . Write the sum in sigma notation and calculate the sum (if possible) that will be the upper limit of this population.
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OpenStudy (anonymous):
PLEASE HELP :(
OpenStudy (anonymous):
@kc_kennylau
OpenStudy (kc_kennylau):
What's the common ratio?
OpenStudy (kc_kennylau):
\[\Sigma=\frac{a_1}{1-r}\]
OpenStudy (anonymous):
1/5
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OpenStudy (anonymous):
one fifth is the common ratio
OpenStudy (kc_kennylau):
Use the formula that I just gave you
OpenStudy (anonymous):
alright give me a sec
OpenStudy (anonymous):
whats r?
OpenStudy (kc_kennylau):
The common ratio
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OpenStudy (kc_kennylau):
Okay I shouldn't have used \(\Sigma\) as the sum
OpenStudy (anonymous):
im completely lost im sorry
OpenStudy (kc_kennylau):
The sum \(S\) of a geometric series with the first term being \(a_1\) and the common ratio being \(r\) is given by the formula \(S=\dfrac{a_1}{1-r}\)
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
4699/5?
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OpenStudy (kc_kennylau):
And if you have to write it in sigma notation, \(\displaystyle\Large\sum_{n=1}^\infty a_1r^{n-1}\)
OpenStudy (anonymous):
939.8
OpenStudy (kc_kennylau):
Nope, 939.8 isn't what I got, mind showing us your steps?
OpenStudy (anonymous):
um yea i divided 940 by 1 minus 1/5
OpenStudy (kc_kennylau):
It's 940 divided by (1 minus 1/5) not (940 divided by 1) minus 1/5 ...
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OpenStudy (anonymous):
ohh ok
OpenStudy (anonymous):
1175?
OpenStudy (kc_kennylau):
Yep
OpenStudy (anonymous):
so wat do i do now?
OpenStudy (kc_kennylau):
Well you have done the second part
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OpenStudy (kc_kennylau):
The first part would be writing it as \(\displaystyle\Large\sum_{n=1}^\infty 940\times\left(\frac15\right)^{n-1}\)
OpenStudy (anonymous):
ok i did that
OpenStudy (kc_kennylau):
Then you'd have done everything
OpenStudy (anonymous):
OpenStudy (anonymous):
the sum is 1,175
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OpenStudy (anonymous):
yea its the other one the one that u did but the sum is 1,175 thank u so much
OpenStudy (kc_kennylau):
the lower limit would be i=0
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
is there any way u could help me with my last one?
OpenStudy (kc_kennylau):
If that's another question please open a new post
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