Find 3sqrt i
\[\sqrt[3]{i}\]
Draw it out in an Argand's diagram or however it's called because I can't spell
kenny can u help me after?
what is that diagram?
|dw:1397926352627:dw|
....I have no idea what that is suppose to be.... how do I graph the equation on that?
Wait, ignore what I've said, I've got another approach
Do you know the DeMorgan's theorem?
No I meant De Moivre's formula https://en.wikipedia.org/wiki/De_Moivre's_formula
Express \(i\) in terms of \(\cos\theta+i\sin\theta\) first?
|dw:1397926472928:dw|
okay, but there's only a 3, I don't know how to start.
Express i in terms of cosθ+isinθ first, and I'll tell you what to do next
But thats what I dont understand. can you give me an example?
Okay, a table for you: \[\begin{array}{rcl} 1&=&\mbox{cis}0^\circ\\ i&=&\mbox{cis}90^\circ\\ -1&=&\mbox{cis}180^\circ\\ -i&=&\mbox{cis}270^\circ \end{array}\]
Where \(\mbox{cis}\theta=\cos\theta+i\sin\theta\)
It'd be best if you memorize this table
Okay so \[cis \theta=\cos \theta+ i \sin \theta\] what do I do after this with the original equation?
well...
If you read it carefully...
\(\mbox{cis}\theta=\cos\theta+i\sin\theta\) isn't an equation...
Okay I shouldn't have been that lazy, wait a minute
From what you said I got \[\sqrt{2}/3+1/2 i\] is that close?
\[\begin{array}{rcl} 1&=&\cos0^\circ+i\sin0^\circ\\ i&=&\cos90^\circ+i\sin90^\circ\\ -1&=&\cos180^\circ+i\sin180^\circ\\ -i&=&\cos270^\circ+i\sin270^\circ \end{array}\]
This is the table
no wait \[\sqrt{3}/2+1/2 i\]
Wow that's a surprise I didn't expect
you to get the correct answer in the first try :)
Im' not bad at math when I understand it....I read through another definition that told me what to do with the original equation. Thanks for the help, I wouldn't have understood it without the table and stuff.
No problem :)
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