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Mathematics 15 Online
OpenStudy (anonymous):

someone can help me with Writing the Equation of a Line???? please

OpenStudy (anonymous):

what do you need help with exactly? like a graph?

OpenStudy (anonymous):

yees. i need help with this assessment.. Now it is your turn to plan the trajectories required to launch a spacecraft through a specific route in space. The launch area is identified on the map below. Launch Area:___(1, 2)___ Point A:___(0, 3)___ Point B:___(-3, 0)___ Point C:___(-1, -4)___ 1)Graph the cordinates of the specifics points in space your spacecraft will travel to. You must show your work on each question below. 2)Determine the equation of the line, in standard form, that will get your spacecraft from the Launch Area to Point A. 3)Determine the equation of the line, in point-slope form, that will get your spacecraft from Point A to Point B. 4)Determine the equation of the line, in slope-intercept form, that will get your spacecraft from Point B to Point C. 5)Determine the equation of the line, in slope-intercept form, that will get your spacecraft from Point B to Point C. 6)Reflect back on this scenario and each equation you created. Would any restrictions apply to the domain and range of those equations? Explain your reasoning using complete sentences.

OpenStudy (anonymous):

can you help me with something?

OpenStudy (anonymous):

I'll try but no promises... your going to have to give me a minute or two

OpenStudy (anonymous):

okaay

OpenStudy (anonymous):

ok so I graphed the points and for #1 I used the slope form for the (1,2) and (0,3) to find the slope…. and then to find the y intercept used coordinate (0,3) and the slope in the formula y=mx+b to finally get y=-x+3 …. does that sound right to you?

OpenStudy (anonymous):

since they wanted it in standard form I added x to y and got x+y=3….

OpenStudy (anonymous):

yes, i think so. So the answer for #2 is x+y=3 ?

OpenStudy (anonymous):

yes that is what i got

OpenStudy (anonymous):

thank u. how about #3 ?

OpenStudy (anonymous):

ok one minute

OpenStudy (anonymous):

suree

OpenStudy (anonymous):

so do you know what point slope form is?

OpenStudy (anonymous):

y−y1=m(x−x1) ??

OpenStudy (anonymous):

yep now find the slope of the 2 coordinates.

OpenStudy (anonymous):

after that use coordinate of point be in the point slope form then you are done with #3

OpenStudy (anonymous):

sorryyy. I had to leave a little bit. continuing, then the answer is x +3?

OpenStudy (anonymous):

are you still here?

OpenStudy (anonymous):

I am soooooo sorry I had to leave as well

OpenStudy (anonymous):

but to answer your previous question yes that is right but make sure that it is set up y-0=1(x+3) because it must be set up in point slope form.

OpenStudy (anonymous):

its okay , im confused now. on the next one #4 I got -2x-6 .. isn't this right?

OpenStudy (anonymous):

so are you confused with #3 and why it is y-0=1(x+3)?

OpenStudy (anonymous):

yess, I thought it was just x+3

OpenStudy (anonymous):

no, the question asks for point slope form which is y-y1=m(x-x1), so even though it seems like the zero doesn't matter in the equation in reality it does. that's why it is y-0=1(x+3)

OpenStudy (anonymous):

are you with me?

OpenStudy (anonymous):

yees, but y1 is not 0 . it is 3? thats why i'm confused

OpenStudy (anonymous):

y−y1=m(x−x1) y-3=1(x-0) y-3=1x y=x+3 I did like that. idk if is right

OpenStudy (anonymous):

ok so you used point a as your coordinate I used point b…. i really don't know which should be used but in essence you don't want to simplify anything you leave it at step 2 y-3=1(x-0) because that is point slope form.

OpenStudy (anonymous):

for #4 you did it right… y=-2x-6

OpenStudy (anonymous):

wait , then the answer is y-3=1(x-0) or y-0(x+3) ?

OpenStudy (anonymous):

…. see that's what not clear to me the question gives you 2 different coordinates which mean you have to pick one of them… I would put both answers just in case.

OpenStudy (anonymous):

oh, okay . so #5 I got Y= -1x+3 . Is this right?

OpenStudy (anonymous):

… #4 and #5 are the same question is there a type o ?

OpenStudy (anonymous):

yess

OpenStudy (anonymous):

so my answer is correct?

OpenStudy (anonymous):

for #4 yes… y=-2x-6

OpenStudy (anonymous):

how about #5 ?

OpenStudy (anonymous):

#5 says the exact as #4 so is there a type o?

OpenStudy (anonymous):

ohhh right.. question #5 is wrong . That would be 5)Convert the equations you arrived at in question 2 and into slope-intercept form. Make sure to include all of your work.

OpenStudy (anonymous):

now my answer makes sense?

OpenStudy (anonymous):

Y= -1x+3

OpenStudy (anonymous):

yes that's right :D

OpenStudy (anonymous):

haha ok. can u help with the last one? I have no idea.

OpenStudy (anonymous):

um…. I would say x and y \[\neq 0\] or x and y \[\ge 0\] … I'm not sure…. hope I've helped :/

OpenStudy (anonymous):

okay, thank you so much! You helped me a lot! :))

OpenStudy (anonymous):

YAY!!! you've made my day!!!

OpenStudy (anonymous):

:D

OpenStudy (anonymous):

haha :D

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