Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

x^3+64=0

OpenStudy (anonymous):

x=4

OpenStudy (anonymous):

honestly i don't know what its called ill type the answer choices

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

-4, -2+2i(square root)3 and -2-2i(square root)3 -4, 2+2i(square root)3 and 2-2i(square root)3 -4, 2+i(square root)3 and 2-i(square root)3 -4, 2+2(square root)3 and 2-2(square root)3

OpenStudy (whpalmer4):

@TheOcean are you sure about that? \[x^3+64 = 0\]\[(4)^3 + 64 = 0\]\[64+64=0\]

OpenStudy (anonymous):

i would still say tht X=4. like @tgawade said

OpenStudy (whpalmer4):

Come on, it doesn't satisfy the original equation!

OpenStudy (anonymous):

thats not what its asking me to do -4, -2+2i(square root)3 and -2-2i(square root)3 -4, 2+2i(square root)3 and 2-2i(square root)3 -4, 2+i(square root)3 and 2-i(square root)3 -4, 2+2(square root)3 and 2-2(square root)3 these are the answer choices

OpenStudy (whpalmer4):

\[x^3+64 = 0\]\[x^3 +64 - 64 = 0-64\]\[x^3 = -64\]

OpenStudy (anonymous):

|dw:1397936302653:dw|

OpenStudy (whpalmer4):

there are two additional roots to find... The complex roots will be symmetrically located in the complex plane. They will all have magnitude = 4. If you plot the answer choices, you should be able to figure it out even if you don't understand the math.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!