x^3+64=0
x=4
honestly i don't know what its called ill type the answer choices
ok
-4, -2+2i(square root)3 and -2-2i(square root)3 -4, 2+2i(square root)3 and 2-2i(square root)3 -4, 2+i(square root)3 and 2-i(square root)3 -4, 2+2(square root)3 and 2-2(square root)3
@TheOcean are you sure about that? \[x^3+64 = 0\]\[(4)^3 + 64 = 0\]\[64+64=0\]
i would still say tht X=4. like @tgawade said
Come on, it doesn't satisfy the original equation!
thats not what its asking me to do -4, -2+2i(square root)3 and -2-2i(square root)3 -4, 2+2i(square root)3 and 2-2i(square root)3 -4, 2+i(square root)3 and 2-i(square root)3 -4, 2+2(square root)3 and 2-2(square root)3 these are the answer choices
\[x^3+64 = 0\]\[x^3 +64 - 64 = 0-64\]\[x^3 = -64\]
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there are two additional roots to find... The complex roots will be symmetrically located in the complex plane. They will all have magnitude = 4. If you plot the answer choices, you should be able to figure it out even if you don't understand the math.
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