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Mathematics 12 Online
OpenStudy (rock_mit182):

A committee is going to select 30 students from a pool of 1000 to receive scholarships. How may ways could the students be selected if each scholarship is worth (a) the same amount? (b) a different amount?

OpenStudy (rock_mit182):

@wagnermar cpuld you help me out ?

OpenStudy (anonymous):

sorry i dont know how to solve this.... they are both very large numbers

OpenStudy (rock_mit182):

Thanks anyway

OpenStudy (anonymous):

In (a) the order of selection doesn't matter, so you're counting combinations. That's C(1000,30) = 1000!/(970! 30!), though the factorial form will blow up on most real calculators. It's about 2.43x10^57. In (b), each order of selection is different (the same students selected in a different order receive different amounts), so you're counting permutations. P(1000,30) = 1000!/30!, or about 6.44x10^89.

OpenStudy (rock_mit182):

holy trap you're tight biggest answer I've ever seen

OpenStudy (rock_mit182):

I'm going to trust in you, thanks a lot beautiful and smart girl

OpenStudy (anonymous):

no problem! :D

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