A committee is going to select 30 students from a pool of 1000 to receive scholarships. How may ways could the students be selected if each scholarship is worth (a) the same amount? (b) a different amount?
@wagnermar cpuld you help me out ?
sorry i dont know how to solve this.... they are both very large numbers
Thanks anyway
In (a) the order of selection doesn't matter, so you're counting combinations. That's C(1000,30) = 1000!/(970! 30!), though the factorial form will blow up on most real calculators. It's about 2.43x10^57. In (b), each order of selection is different (the same students selected in a different order receive different amounts), so you're counting permutations. P(1000,30) = 1000!/30!, or about 6.44x10^89.
holy trap you're tight biggest answer I've ever seen
I'm going to trust in you, thanks a lot beautiful and smart girl
no problem! :D
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