Question

...

Answer 1

may help: http://stattrek.com/hypothesis-test/difference-in-proportions.aspx

Answer 2

It is the same idea as last time, but now you are comparing proportions rather than means.

But you use the proportion standard error:
You hypothesis test is:
\[H_0: p = 0.52\\
H_1: p > 0.52 \]
Your test statistic is
\[\frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}} \]
I just used general notation so you know what's going on. \(p_0=0.52\), the null value, and \(\hat{p}=0.65\) your calculated value

Answer 3

And this statistic follows a standard normal distribution (approximately), so you look up the appropriate value in a standard normal table to find the rejection region.

Answer 4

I can check a), I'll try it out

Answer 5

Calculation is correct. But when you are using proportions, the statistic is from a normal(0,1) distribution rather than a t distribution. This comes from the fact that the proportion are coming from a binomial type of distribution, but is approximately normal under the central limit theorem.

Answer 6

yes

Answer 7

Your welcome

Which formula did you use for a)?

Answer 8

It calculates it automatically?

Answer 9

Oh never mind, it is correct... I pressed an extra 0 by accident on my end :P

Answer 10

Sorry about that