Question

Please help me someone

Answer 1

A golf ball is chipped into the air from a small hill with an upward velocity of 50 ft/s. Its height h in feet after t seconds is given by the function h=-16t^2+50t+10. What is the maximum height in feet that the ball reaches? Round your answer to the nearest whole number.

Answer 2

\[Equation: h=-16t^2+50t+10\]

Answer 3

First find out derivative of function to get critical point

Answer 4

???

Answer 5

okay its is quadratic equation so maximum or minimum point would be at vertex correct ?

Answer 6

Yes

Answer 7

So can you try to find vertex for it ?

Answer 8

with the quadratic equation?

Answer 9

use (-b/2a) to fin out vertex

Answer 10

Getting this ??

Answer 11

yes

Answer 12

So vertex would be ---- ?

Answer 13

\[\frac{ -50 }{ 2*-16 }\]

Answer 14

50/32

Answer 15

?

Answer 16

Perfect ......

Answer 17

So now what?

Answer 18

Now we need to find out value of given function at this point can you try for it ?

Answer 19

How can I do that... I mean what's the equation

Answer 20

We are having function as h=-16t^2+50t+10 just plug value of of t =( 50/32) into this equation and try to simplify it can you try ?

Answer 21

I will

Answer 22

So this is nothing but height of ball which is ------ ?

Answer 23

2035/16

Answer 24

?

Answer 25

Please check it once

Answer 26

it should be ( 785/16 )

Answer 27

Byeeeeee :)

Answer 28

\[h=-16(\frac{ 60 }{ 32 })^2+50(\frac{ 50 }{ 32 })+10\]

Answer 29

are you sure @suyogsomavanshi

Answer 30

OH now I see why... Thank you @suyogsomavanshi