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Mathematics 7 Online
OpenStudy (anonymous):

Find the derivative of the function. But don't simplify the answer

OpenStudy (anonymous):

\[f(x)= (5x^3+3x^2-7x)^{7.5}\]

OpenStudy (anonymous):

Chain rule is used right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

i dont know how to do that

OpenStudy (anonymous):

(derivative of outside) x (derivative of inside) x (derivative of inside inside ) x (derivative of inside inside inside... )

OpenStudy (anonymous):

nom sayin?

OpenStudy (anonymous):

the answer will be \[7.5(15x^2+6x-7)(5x^3+3x^2-7x)^{8.5}\]

OpenStudy (anonymous):

Am i correct?

OpenStudy (anonymous):

not quite

OpenStudy (anonymous):

there's only 2 layers, so it should only be the derivative outside multiplied by the derivative inside

OpenStudy (anonymous):

and you're supposed to subtract the exponent by 1, not add 1.

OpenStudy (anonymous):

i dont understand.

OpenStudy (anonymous):

the exponent will be 6.5

OpenStudy (anonymous):

if f(x) = a^7.5 then f'(x) = 7.5a^6.5 x (derivative of a) bring the exponent down and subtract it by one.

OpenStudy (anonymous):

nom sayin?

OpenStudy (anonymous):

i get the exponent. I dont understand the derivative inside outside thing that you said

OpenStudy (anonymous):

treat the stuff inside the bracket as another function then f(x) = [f(g)]^7.5 then f'(x) = 7.5 [f(g)] ^6.5 x f'(g) the exponent is multiplied by the function and subtracted by one

OpenStudy (anonymous):

nom sayin?

OpenStudy (anonymous):

7.5(5x^3+3x^2-7x)^6.5x(15x^2+6x-7)

OpenStudy (anonymous):

??

OpenStudy (anonymous):

yes.

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