[Newton's Laws - Mechanics] A 10 kg monkey climbs up a massless rope that runs over a frictionless tree limb and back down to a a 15 kg package on the ground.

What is the magnitude of the least acceleration the monkey must have if it is to lift the package off the ground?

#I tried making a free body diagram and take in account all the forces both monkey and the package are experiencing, however I am confused as to how to solve it. It would be great if you could help with that.

Question

[Newton's Laws - Mechanics] A 10 kg monkey climbs up a massless rope that runs over a frictionless tree limb and back down to a a 15 kg package on the ground.

What is the magnitude of the least acceleration the monkey must have if it is to lift the package off the ground?

#I tried making a free body diagram and take in account all the forces both monkey and the package are experiencing, however I am confused as to how to solve it. It would be great if you could help with that.

anonymous · Answer

This is the diagram

vincent-lyon.fr · Answer

Hint: what is the least tension in the rope necessary to lift the crate?

anonymous · Answer

Equivalent to the weight of the package.

vincent-lyon.fr · Answer

Ok, so same tension will act on the left side of the rope too.

Now use N's 2nd and 3rd laws to find out the acceleration of the monkey.

anonymous · Answer

Thanks a lot. I got the answer and it's right (checked the solution manual). 4.9m/s^2.

anonymous · Answer

I was hoping to find a bit more insight on how to generally draw free body diagrams in an effective way to crack the problem because we're clearly neglecting the effects of Normal force on the crate. I'm confused how do we go about that.

vincent-lyon.fr · Answer

If the crate is accelerating up, it means it will lose contact with the ground, so normal force is zero and need not be drawn at all.