Question

Please help

Answer 1

\[y=-x^2+7x-10\]

Answer 2

Using the quadratic equation I got 8 and -1

Answer 3

But the possible answers are completely different

Answer 4

@ganeshie8

Answer 5

must have made some arithmetic mistake somewhere

Answer 6

\(\large -x^2+7x-10 = 0\)


\(a = ?\)
\(b = ?\)
\(c = ?\)

Answer 7

a=-1
b=7
c=-10

Answer 8

Yes !

Answer 9

your quadratic formula to solve zeroers :

\(\large x = \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\)

Answer 10

plugin the numbers

Answer 11

\[\frac{ x=-7\pm \sqrt{7^2-4(-1)(-10)} }{ 2(-1) }\]

Answer 12

\(\large x = \dfrac{-7 \pm \sqrt{7^2-4(-1)(-10)}}{2(-1)}\)


\(\large x = \dfrac{-7 \pm \sqrt{49- 40}}{-2}\)

\(\large x = \dfrac{-7 \pm \sqrt{~9}}{-2}\)

\(\large x = \dfrac{-7 \pm 3}{-2}\)

\(\large x = \dfrac{-7 + 3}{-2}, ~~ \dfrac{-7 - 3}{-2} \)

\(\large x = \dfrac{-4}{-2}, ~~ \dfrac{-10}{-2} \)

\(\large x = 2, ~~ 5 \)

Answer 13

^^ let me knw if smthng doesnt make sense

Answer 14

Oh now I see

Answer 15

I forgot to evaluate the radical of 9

Answer 16

haha I see :)

Answer 17

Thank you

Answer 18

u wlc ^_^