Question

find the x,y and z intercepts for the equation 2x-6y-3z=12

Answer 1

your idea?

Answer 2

for x-intercept, y and z have to be 0, think about it. So if y and z are zero, then 2x is 12 and x=6. same for the others

Answer 3

whats the cordiantes then?

Answer 4

would it be 0,0,6?

Answer 5

it would be (6,0,0) for x-intercept, since coordinates are written in this manner (x,y,z)

Answer 6

It's hard to explain the problem geometrically because it relates to cal3 which is not the stuff you have here (I assume that)
so that, for this kind of problem, to find x- intercept, let y =0 , z =0 on the expression to find it out
to find y-intercept, let other two =0 ( I mean x, z)
to find z-intercept, do the same.
Dat sit

Answer 7

thank you for the answer :)

Answer 8

whats the -x,y- and z- intercepts for the equation 9x+3y-6z=18

Answer 9

again, x-intercept will be when y=0 and z=0. so 9x=18 x=2.
y-intercept will be when x=0,z=0 so 3y=18 y=6
z-intercept will be when x=0,y=0 so 6z=18 z=3

sorry thats a bit late :P i was out and about climbing on roofs haha

Answer 10

coordinates (2,0,0) and (0,6,0) and (0,0,3)