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Mathematics 15 Online
OpenStudy (gabylovesyou):

FInd the perimeter of the image

OpenStudy (gabylovesyou):

37 units 38 units 39 units 40 units

OpenStudy (gabylovesyou):

@ash2326 @phi

ganeshie8 (ganeshie8):

to find the perimeter of given shape, you need to find out sides first

ganeshie8 (ganeshie8):

perimeter = sum of all sides

ganeshie8 (ganeshie8):

know how to find the length of sides on coordinate plane ?

OpenStudy (gabylovesyou):

distance formula ?

ganeshie8 (ganeshie8):

yes, but for that u need to figure out coordinates of points and plug them in the formula... which is a pain... and u need to do it for 5 times... since u have 5 sides

ganeshie8 (ganeshie8):

there is a simpler way to do this, which uses the distance formula in disguise...

OpenStudy (gabylovesyou):

ok..

OpenStudy (gabylovesyou):

whats the simpler way ?

ganeshie8 (ganeshie8):

ganeshie8 (ganeshie8):

use pythagorean theorem : that red side = \(\sqrt{2^2+6^2} = \sqrt{40}\)

ganeshie8 (ganeshie8):

this is exact same as distance formula, but this is felt simple because, you're not plugging in the coordinates... instead you're just counting the number of grids...

ganeshie8 (ganeshie8):

use whichever u feel is easy...

OpenStudy (gabylovesyou):

how did u solve that ^ ... like how did u get 40 ?

ganeshie8 (ganeshie8):

the goal is to find the length of all sides and add up

OpenStudy (gabylovesyou):

ok..

ganeshie8 (ganeshie8):

did u get how I got : red side = \(\sqrt{2^2+6^2} \)

ganeshie8 (ganeshie8):

?

OpenStudy (gabylovesyou):

i know how u got the 2 and the 6... just not the 40 ...

ganeshie8 (ganeshie8):

oh cool :) ive just skipped a step : red side = \(\sqrt{2^2+6^2} = \sqrt{4+36} = ?\)

OpenStudy (gabylovesyou):

ohhh ok

ganeshie8 (ganeshie8):

find the lengths of remaining sides in any way u wish, and add them all up

OpenStudy (gabylovesyou):

for pt it would be 4^2 + 10^2

OpenStudy (gabylovesyou):

which is 116

ganeshie8 (ganeshie8):

Yes ! dont forget the sqrt

OpenStudy (gabylovesyou):

ok...

ganeshie8 (ganeshie8):

\(PT^2 = 4^2 + 10^2\) \(PT = \sqrt{4^2 + 10^2} = \sqrt{116}\)

OpenStudy (gabylovesyou):

TS is 7

OpenStudy (gabylovesyou):

how do i do SR O.o

ganeshie8 (ganeshie8):

OpenStudy (gabylovesyou):

50 ok..

ganeshie8 (ganeshie8):

*sqrt...

OpenStudy (gabylovesyou):

right... lol and then the last side is sqrt 61 ?

OpenStudy (gabylovesyou):

do i add them all ?

ganeshie8 (ganeshie8):

yup ! perimeter = length around a shape = sum of all sides

OpenStudy (gabylovesyou):

sqrt 274

OpenStudy (gabylovesyou):

?

ganeshie8 (ganeshie8):

lol no

ganeshie8 (ganeshie8):

you cannot add radicals like that

ganeshie8 (ganeshie8):

\(\large \sqrt{a} + \sqrt{b} + \sqrt{c} ~ \ne ~ \sqrt{a + b+ c}\)

OpenStudy (gabylovesyou):

hm i got 60 ;/

ganeshie8 (ganeshie8):

You got : \(QP = \sqrt{40}\) \(PT = \sqrt{116}\) \(TS = 7\) \(SR = \sqrt{50}\) \(RQ = \sqrt{61}\)

ganeshie8 (ganeshie8):

right ?

OpenStudy (gabylovesyou):

yes

ganeshie8 (ganeshie8):

plug each sqrt in ur calcualtor and add them all

ganeshie8 (ganeshie8):

\(QP = \sqrt{40} = \color{red}{6.32}\) \(PT = \sqrt{116} = \color{red}{10.77}\) \(TS = 7 = \color{red}{7}\) \(SR = \sqrt{50} = \color{red}{7.07}\) \(RQ = \sqrt{61} = \color{red}{7.81}\) --------------------------------------- perimeter = \(\color{Red}{?}\)

OpenStudy (gabylovesyou):

38. 97

OpenStudy (gabylovesyou):

so should i put 39 ?

OpenStudy (gabylovesyou):

or try it the long way to double check

ganeshie8 (ganeshie8):

rounding it becomes : \(38.97 \approx 39\)

ganeshie8 (ganeshie8):

Nope, both are one and same... you may try for practice if u want maybe :)

OpenStudy (gabylovesyou):

okay :) thank you!

ganeshie8 (ganeshie8):

np :)

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