Question

The function f(x) =4x^4-2x^3+1 has a point of inflection at x=?

Answer 1

Find the second derivative of the function.
Set it equal to zero.
Solve for x.

Answer 2

Any work on this ??

Answer 3

I found the second derivative, 48x^2-12x. But im not sure how to solve it when I set x=0

Answer 4

well you set the 2nd derivative equal to zero... and you'll have 2 points of infection so if

\[\frac{d^2y}{dx^2} = 48x^2 - 12x\]

then let\[\frac{d^2y}{dx^2} = 0\]

so solve

\[0 = 48x^2 - 12x\]

Answer 5

one of the infection points... is a horizontal point of inflection

Answer 6

Factor the right side.