Question

(3xy+3xz)/(4x^2y+4x^2z)

Answer 1

Are we ask to simplify ?

Answer 2

yes

Answer 3

i got 3/4x, but he counted it wrong

Answer 4

Factor out the denominator

Answer 5

4x^2(y+z)

Answer 6

now separate the fraction\[\frac{ 3xy }{ 4x ^{2}(y+z)}+\frac{ 3xz }{ 4x ^{2}(y+z) }\]

Answer 7

look at the first part of the problem, what are the like terms? Is there any way to cancel out those like terms?

Answer 8

the x right?

Answer 9

thats one of them, there is another

Answer 10

the y

Answer 11

yes, now we need to cancel those out in the numerator and denominator. So to do that we need to factor out the y.\[\frac{ 3xy }{ 4x ^{2}y(1-z) }\]

Answer 12

once you cancel these what would the fraction look like?

Answer 13

keep in mind to divide exponents you subtract.

Answer 14

3/4x-z ?

Answer 15

almost, you would subtract the denominator exponent from the numerator.

Answer 16

what do you mean?

Answer 17

\[x ^{1-2}=x ^{-1}\]

Answer 18

so 3/4x^-1 -z ? or would it become a -4x?

Answer 19

\[\frac{ 3 }{ 4x ^{-1}(1-z) }\]\[\frac{ 3 }{ 4x ^{-1}-4x ^{-1}z }\]

Answer 20

would you factor out the denom?

Answer 21

We foiled the denom. To factor it would leave you with what we got after canceling the like terms, so we would leave it like that for the moment, and do the same to the second part of the fraction.

Answer 22

so would it be : 3/4x^-1y?

Answer 23

it would be \[\frac{ 3 }{ 4x ^{-1}-4x ^{-1}y }\] giving you\[\frac{ 3 }{ 4x ^{-1}-4x ^{-1}z }+\frac{ 3 }{ 4x ^{-1}y }\] What do you think the next step would be?

Also a side note in case you didn't already know is that underneath the text box are blue buttons, the equation button lets you enter equations instead of having to use symbols like ^ to represent exponents. The draw button lets you draw, add graphs, tables, ect. then the attach file lets you attach a file. and the post lets others see what you wrote.

Answer 24

sorry I left out a part of the equation, \[\frac{ 3 }{ 4x^{-1} -4x ^{-1}z}+\frac{ 3 }{ 4x ^{-1}-4x ^{-1} y}\]

Answer 25

\[\frac{ 3(-4x ^{-1}z) }{4x^{-1}y-4x^{-1}z }\]

Answer 26

you need to make common denominators by cross multiplying\[\frac{ 3(4x ^{-1}-4x ^{-1}y) }{4x ^{-1}-4x ^{-1}z(4x ^{-1}-4x ^{-1}y) }+\frac{ 3(4x ^{-1}-4x ^{-1}z) }{4x ^{-1}-4x ^{-1}y(4x ^{-1}-4x ^{-1}z) }\]

Answer 27

do you multiply the the denominators?

Answer 28

yes, im calculating it right now, so give it a go, and we'll see if we match results

Answer 29

alright, I got an answer that cannot possibly be the answer. So if you'd like I can look at it, see where I went wrong, and back to you when I can. Sometimes I need to step away for a while and come back with a totally new perspective. So if you have the time, that's what I can do for you. If not, I recommend re-posting the question and having some one else help you out.

Answer 30

Sorry about that :(

Answer 31

ok yeah i got lost as well.

Answer 32

alright, I'll mail you when I got it figured out.

Answer 33

okay thank you!