Question

HELP ME PLEASE DUDES AND DUDETTES .!!!

The square root of negative 9 divided by (4-7i) - (6-6i)

Answer 1

-6.32307692 + 6.18461538 i

Answer 2

So let's tackle the numerator first. \[\sqrt{-9} = \sqrt{9} * \sqrt{-1} = 3i\]Then, the denominator is simply\[(4-7i)-(6-6i) = 4-7i-6+6i = 10-i\]So our answer is \[\frac{ 3i }{ 10-i }\]But we have to make sure that we don't have imaginary numbers in the denominator! So we get\[\frac{ 3i }{ 10-i } * \frac{ 10+i }{ 10+i } = \frac{ 30i + 3i^2 }{ 100 - 10i + 10i - i^2 } = \frac{ -3+30i }{ 101 }\] Makes sense? Let me know if you have any problems with any of the steps.

Answer 3

@TakerraT, are you there?

Answer 4

yes im here . thank you so much

Answer 5

No problem! Is everything clear?

Answer 6

i wasnt one of my answer choices... do yu wanna see my answer choices?

Answer 7

Sure.

Answer 8

Oh, arithmetic mistake. Second line should say \[-2-i\]So your next line would say\[\frac{ 3i }{ -2-i } * \frac{ -2+i }{ -2+i } = \frac{ -3-6i }{ 5 }\] So THAT'S your final answer. Sorry.

Answer 9

a. -3-6i/5 b. 39-6i/-9 c. -39-6i/17 d. 3-6i/3

Answer 10

Thank You :D

Answer 11

No problem!

Answer 12

(8 + 3i)(3 + 5i) :p

Answer 13

wouldnt it be 24+15i^2 ?

Answer 14

Yeah, but don't forget your middle terms! You have\[(8+3i)(3+5i) = 25 + 40i +9i + 15i^2 = 25 + 49i - 15 = 10+49i\]See?

Answer 15

Correction: \[9+49i\]I cannot add today.

Answer 16

im sooo confused lol >.<

Answer 17

Are you familiar with FOIL?

Answer 18

As in, do you know how to multiply out something of the form (a+b)(c+d)?

Answer 19

yes i am :) im not that good in math lol

Answer 20

OK. So what are you confused about?

Answer 21

ill inbox yu lol >.<