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Mathematics 13 Online
OpenStudy (anonymous):

I need help with this exponent problem! It will be really quick. Thanks in advance! ~Micah K.

OpenStudy (anonymous):

OpenStudy (anonymous):

@precal

OpenStudy (whpalmer4):

Can you write both terms with fractional exponents instead of radical signs?

OpenStudy (campbell_st):

well write them in index form \[3^{\frac{1}{2}} \times 3^{\frac{1}{5}}\] the rule for multiplying the same base is add the powers... hope that helps you...

OpenStudy (whpalmer4):

You'll have the same base for both, so to multiply, just add the exponents.

OpenStudy (nikato):

This is how I would do it

OpenStudy (anonymous):

What is the second fraction? It is too small to see.

OpenStudy (campbell_st):

remember \[x^a \times x^b = x^{a + b}\]

OpenStudy (campbell_st):

well the solution posted by @nikato is incorrect....

OpenStudy (whpalmer4):

Nth root of something is something to the 1/n power

OpenStudy (anonymous):

Thanks for the image! I guess that I just have to use the rational exponent property. Thank you both.

OpenStudy (nikato):

Oops thanks Campbell So it'll be 3 ^(1/5 + 1/2)

OpenStudy (anonymous):

Okay, cool. Can you help me with one more? My lesson doesn't really talk about this concept much.

OpenStudy (campbell_st):

so re-write as a starting point \[\sqrt[3]{5}\] in index form...?

OpenStudy (anonymous):

5^1 over a

OpenStudy (anonymous):

@nikato "So it'll be 3 ^(1/5 + 1/2)" I think that you mean 3 ^(1/5 times 1/2).

OpenStudy (anonymous):

@campbell_st I think that I understand where you are getting at.

OpenStudy (campbell_st):

well for the 1st question you posted, you'll need to simplify the fraction... 1/2 + 1/5 =

OpenStudy (anonymous):

Ooohhh my bad. So the answer is 5 to the 7 tenths power, not 1 tenth power.

OpenStudy (anonymous):

I think that the answer to the second question is 5 to the 1 sixth power. Am I correct?

OpenStudy (whpalmer4):

Yes, that is correct.

OpenStudy (campbell_st):

thats correct... for both questions

OpenStudy (anonymous):

Okay, thank you guys!!

OpenStudy (whpalmer4):

you're welcome

OpenStudy (anonymous):

Thanks for the medal.

OpenStudy (anonymous):

@campbell_st

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