Question

Integrate

Answer 1

\[\int\limits_{}^{}(12e^3x+2x+\frac{ 7 }{ x })dx\]

Answer 2

@radar

Answer 3

@Juarismi @Hero

Answer 4

\[\int\limits_{}^{}(12e^3x+2x+\dfrac{ 7 }{ x })dx = \int12e^3x \space dx + \int 2x \space dx + \int \dfrac{7}{x}\space dx\]
\[=12e^3 \int x \space dx + 2 \int x \space dx + 7 \int \frac{1}{x} dx\]

Answer 5

@Sephora

Answer 6

doesnt it suppose to be \[12\int\limits_{}^{}e^3xdx\]

Answer 7

\(e^3\) is a constant

Answer 8

where did you got 1/x in 7/x?

Answer 9

\(\dfrac{7}{x} = \dfrac{7}{1} \times \dfrac{1}{x} = 7\left(\dfrac{1}{x}\right)\)