Which is the equation of the line? http://static.k12.com/calms_media/media/1299500_1300000/1299544/1/adb96b45350fd42ac9bf15e721fcb1840fbe25b0/143713.jpg A. 5x + 3y = 15 B. 5x – 3y = 15 C. –5x + 3y = 15 D. –5x – 3y = –15
The x- and y-intercepts are clear and easy to read in the illustration. Please, would you identify these intercepts?
x= -3 and y=5 @mathmale
Yes, or (-3,0) and (0,50. From these 2 points we need to obtain the slope of this line. Do you know how to do that? If so... m = ?
i dont know how @mathmale
I'm helping several students at once, so am a bit short on time. I will help you to finish this entire problem, but first, I ask you to please look up the equation for 'SLOPE OF A STRAIGHT LINE." We'll need it.
yeah sure m ( the slope) = Y2-Y1/X2-X1 IN OUR CASE we have the intercept on the axis in two points P1(-3,0) P2 (0,5) WHICH lead us to : \[m =\frac{ 5-0 }{ 0-(-3) } =?\]
itsbribro: I was hoping you'd Google "slope of a straight line," as you'd immediately find the formula that you need. roc_mit knows that formula and is showing you how to use it. you will need to know it later on.
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Nice work, both of you! @itsbribro: What do you think the next step should be? Review the original question.
good, youre right, now we are going to find the y- intercept (b), untill now we have y=mx + b m and the variables x and y
no m = the increment of y/ the increment x
x is the indepent variable, that means you can plug as many values as you want
y is the in dependent variable, that means you can find the value of y each time you plug a value in x
you were right with the slope m =5/3
y = 5/3x + b
now in order to find the y-intercept (b) you have to assign for x the value 0
\[y=\frac{ 5 }{ 3 }(0) + b\]
so that means find the poin where x = 0 and y =b, in other words (0,b)
@itsbribro where the line cuts the y- axis at what point makes that ?
b = 5 y = (5/3)x + 5 expressed in other way, would be ?
3y = 5x + 15
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