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Mathematics 21 Online
OpenStudy (anonymous):

Find the area between the curves y = 2x and y= x^2

OpenStudy (anonymous):

did you find where they intersect?

OpenStudy (anonymous):

2x = x^2 , 2x-x^2 = 0, then solve for x ?

OpenStudy (anonymous):

that, or solve it with your eyeballs

OpenStudy (anonymous):

pretty clear they intersect at \(x=0\) and at \(x=2\) right?

OpenStudy (anonymous):

yeah~

OpenStudy (anonymous):

is it also clear that on that interval \(2x>x^2\) ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

then your last job is to find \[\int_0^2(2x-x^2)dx\] and you are done

OpenStudy (anonymous):

oh, ok thanks!

OpenStudy (anonymous):

yw

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