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Find the area between the curves y = 2x and y= x^2
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did you find where they intersect?
2x = x^2 , 2x-x^2 = 0, then solve for x ?
that, or solve it with your eyeballs
pretty clear they intersect at \(x=0\) and at \(x=2\) right?
yeah~
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is it also clear that on that interval \(2x>x^2\) ?
yes
then your last job is to find \[\int_0^2(2x-x^2)dx\] and you are done
oh, ok thanks!
yw
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