Question

Please help! Will medal!!


I need to know how to solve: If s(x) = 2x^2 + 3x - 4, and t(x) = x + 4 then s(x) · t(x) =

Answer 1

(s*t)(x) ?

Answer 2

Not a clue. Sorry

Answer 3

Well, you'd multiply the two values you have.
(2x^2 + 3x-4)(x+4)
I'd highly suggest factoring the first expression (2x^2 + 3x - 4), if you can. :)

Answer 4

Hm, well s(x) * t(x) is same as grabbing s of x and t of x and multiplying them...

(2x^2 + 3x - 4) * (x + 4) = (2x^2 + 3x - 4)(x + 4, now Foil it. Factoring wouldn't do much.

Answer 5

Questions? :O

Answer 6

I don't understand this at all. Sorry

Answer 7

Did you understand why you multiply the two values? :)

Answer 8

Hm, suppose that s(x) is 1, and that t(x) is 2,

\(\ \sf \color{blue}{s(x)} \times \color{red}{t(x)} = \color{blue}{1} \times \color{red}{2} = 2 \) get it now? :O

Answer 9

I don't understand how to foil this.

Answer 10

Except! That because it's more than 1 number or variable, it gets confusing, so use parenthesis. And, s(x) * t(x) = (s*t)(x) ;)

Answer 11

Well, FOIL works like this:
Say you have this:
(x+2)(x+3)

You'd multiply the first two terms first (x and x) to get x^2.
Then you multiply the outside (x and 3) to get 3x
Then the inside (2 and x) to get 2x
Then the last two terms (2 and 3) to get 6
x^2 + 3x + 2x + 6
x^2+5x+6.

FOIL means first, outside, inside, last :)

Answer 12

I hope that makes sense ^^'

Answer 13

Same thing!

If it helps, switch it around, (x+4)(2x^2 + 3x-4)