Question

The solution to which inequality is shown?


http://static.k12.com/calms_media/media/1412500_1413000/1412583/1/dc6b145dc84537ee0bec246d4cdeb4bb57fd98a1/MS_PA_130528_200025.jpg

A.
y + 3 ≥ –1

B.
y + 3 > –1

C.
y + 3 ≤ –1

D.
y + 3 < –1

Answer 1

@Luigi0210

Answer 2

idk this

Answer 3

It would have to be D.. because it is an open circle. Solve the inequality and you get \(y<-4\).. which means every number, less than, but not including -4.

Answer 4

can you help me with a couple @orezsnel

Answer 5

Solve.
-s/3≥6

A.
s ≥ –2

B.
s ≤ –2

C.
s ≥ –18

D.
s ≤ –18

Answer 6

It would be D. The number line shown, shows open circle, so you know the variable, in this case y is not included. so only options left are either \[< or > \]. Your graph is coming from the infinte small number in the left hand side all the way up to -4,so the graph is saying that -4 will be your highest number. but since -4 is not included your variable is less than -4. therefore your answer is \[y<-4\]

Answer 7

Which graph shows the solution of the inequality?

-x/3≥

A. http://static.k12.com/calms_media/media/1402500_1403000/1402861/1/b20376bb82bdd2bdf2209a2285def8370fb99699/MS_PA_130528_200031.jpg

B. http://static.k12.com/calms_media/media/1402500_1403000/1402862/1/ed8fb8fb34c010aad819ee0d3f436276c209d14c/MS_PA_130528_200032.jpg

C. http://static.k12.com/calms_media/media/1402500_1403000/1402863/1/0abd17611caaba4d70411b2dc923386b1cfe7c9c/MS_PA_130528_200033.jpg

D. http://static.k12.com/calms_media/media/1402500_1403000/1402864/1/48609b00488b89b84efb75302a92f5f685716145/MS_PA_130528_200034.jpg

Answer 8

-x/3≥6 i meant to put

Answer 9

The next answer is D. Since 3 is your denominator, the only way to get ride of it, would be to mulitply both sides by 3. The three in 3(s/3) will cancel out. the other side would be 3 x6 which would be 18. so now you have \[-s \ge 18\]. Remember when dividing an inequality with a negative, the sign changes direction. so you end up with \[s \le -18\]

s or x is fine its just a variable :)

Answer 10

Which equation can be used to find the perimeter of a regular octagon with sides of length 12 m?

A.
P = 8 + 12

B.
P = 8(12)

C.
P = 2(8) + 2(12)

D.
P = 12 ÷ 8