Question

Will give a medal... Please help me...



What is the solution of log2x − 5 (25) = 2?

x = −5

x = 2

x = 5

x = 3

Answer 1

is it base or is it multiplying?

Answer 2

2x-5 is the base

Answer 3

okay, logarithm is defined the following way:
\[\log_{b} a=c <=> b ^{c}=a\]
we can read it like this:
"The logarithm with base 'b' of a number 'a' and equal a number 'c' is true only if 'b' to the power of 'c' is equal to 'a'"
applying that to your problem:
\[\log_{2x-5} 25=2\]
applying definition:
\[\log_{2x-5} 25 = 2 <=>(2x-5)^{2}=25\]
so, traducing it, we wiped out the logarithm and made it into a one-variable equality:
\[(2x-5)^{2}=25\]
All you have to do is solve for "x"

Answer 4

So, X= -5? If I am correct.

Answer 5

REmember, when you apply square root it's always plus/minus.

Answer 6

hey did you get this one right

Answer 7

I think she/he did.