Question

whats up guys , can someone explain me how to solve this type of fractions (1+1/x) / ( 1-1/x^2) ,

Answer 1

i know that the answer is x/x-1 ,but i dont know how to do it

Answer 2

\[\dfrac{1 + \dfrac{1}{x}}{1 - \dfrac{1}{x^2}}\]

Answer 3

Is that what you have to begin with?

Answer 4

yep

Answer 5

thats the fraction

Answer 6

do u know how to solve it ,or the name of this fractions , cause i dont know how to do it and i want to know , thank u for answer my question

Answer 7

\[\dfrac{\dfrac{x}{x} + \dfrac{1}{x}}{\dfrac{x^2}{x^2} - \dfrac{1}{x^2}}\]


\[\dfrac{\dfrac{x + 1}{x}}{\dfrac{x^2 - 1}{x^2}}\]
\[\dfrac{x + 1}{x} \div \frac{x^2 - 1}{x^2}\]

\[\dfrac{x + 1}{x} \times \frac{x^2}{x^2 - 1}\]
\[\frac{x + 1}{x} \frac{x^2}{(x + 1)(x - 1)}\]

\[\frac{\cancel{x + 1}}{\cancel{x}} \frac{x^\cancel{2}}{\cancel{(x + 1)}(x - 1)}\]

\[\frac{x}{x - 1}\]

Answer 8

thank u , do u know the name of this fractions

Answer 9

What do you mean? I think maybe complex fractions.

Answer 10

na dont worry and thank u i got it