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OpenStudy (anonymous):

Simplify the complex fraction: (Problem in comments...)

OpenStudy (anonymous):

\[\frac{ \frac{ \frac{ 1 }{ a+1 } +2}{ 1 } }{ a+7 } +7\]

ganeshie8 (ganeshie8):

work numerator separately first work denominator separately next after flip the denominator to convert it to multiplication

OpenStudy (anonymous):

so the 2 & 7, turns into 2/1 & 7/1?

ganeshie8 (ganeshie8):

\(\huge \dfrac{ \dfrac{ \frac{ 1 }{ a+1 } +2}{ 1 } }{ a+7 } +7\) Make the common denominators on numerator and denominator separately : \(\huge \dfrac{ \dfrac{ \frac{ 1 }{ a+1 } +\frac{2(a+1)}{a+1}}{ 1 } }{ a+7 } +\frac{7(a+7)}{a+7}\)

ganeshie8 (ganeshie8):

add both fractions on numerator, add both fraction on denominator

ganeshie8 (ganeshie8):

what do u get ?

OpenStudy (anonymous):

2a +2/a+1 & 7a+49/a+7

ganeshie8 (ganeshie8):

Excellent !

OpenStudy (anonymous):

do I add the 1 to both?

ganeshie8 (ganeshie8):

\(\huge \dfrac{ \dfrac{ \frac{ 1 }{ a+1 } +2}{ 1 } }{ a+7 } +7\) Make the common denominators on numerator and denominator separately : \(\huge \dfrac{ \dfrac{ \frac{ 1 }{ a+1 } +\frac{2(a+1)}{a+1}}{ 1 } }{ a+7 } +\frac{7(a+7)}{a+7}\) Adding fractions on numerator and denominator gives : \(\huge \dfrac{ \frac{ 2a+2 }{ a+1 } } { \frac{1+7a+49}{a+7}}\)

ganeshie8 (ganeshie8):

right ?

OpenStudy (anonymous):

yea, but what about the 1+ in front of the 2 too?

ganeshie8 (ganeshie8):

Good :) was just checking if you're alert or not ;)

ganeshie8 (ganeshie8):

let me correct it

ganeshie8 (ganeshie8):

\(\huge \dfrac{ \dfrac{ \frac{ 1 }{ a+1 } +2}{ 1 } }{ a+7 } +7\) Make the common denominators on numerator and denominator separately : \(\huge \dfrac{ \dfrac{ \frac{ 1 }{ a+1 } +\frac{2(a+1)}{a+1}}{ 1 } }{ a+7 } +\frac{7(a+7)}{a+7}\) Adding fractions on numerator and denominator gives : \(\huge \dfrac{ \frac{ 1+2a+2 }{ a+1 } } { \frac{1+7a+49}{a+7}}\)

OpenStudy (anonymous):

I'm always alert at 4 am lol

ganeshie8 (ganeshie8):

lol, see if that looks okay now...

OpenStudy (anonymous):

yes!

ganeshie8 (ganeshie8):

good :) above expression is same as : \(\huge \dfrac{ \frac{2a+3 }{ a+1 } } { \frac{7a+50}{a+7}}\)

ganeshie8 (ganeshie8):

lastly, flip the denominator to convert it to multiplicaiton

ganeshie8 (ganeshie8):

\(\huge \dfrac{ \frac{2a+3 }{ a+1 } } { \frac{7a+50}{a+7}}\) is same as : \(\huge \frac{2a+3 }{ a+1 } \times \frac{a+7}{7a+50}\)

ganeshie8 (ganeshie8):

putting everything under same fraction gives : \(\huge \frac{(2a+3)(a+7) }{ (a+1)(7a+50) } \)

ganeshie8 (ganeshie8):

we're done !

OpenStudy (anonymous):

That's it?

ganeshie8 (ganeshie8):

thats it, thats the final simplified form

OpenStudy (anonymous):

Why is there sooo many people watching us solve this problem? lol

ganeshie8 (ganeshie8):

cuz you're a brilliant student... everyone likes to help u :)

OpenStudy (anonymous):

Lol they're just staring lmaooo

ganeshie8 (ganeshie8):

thats one of acknowledging the fact that you're doing it correctly and they dont need to pitch in to rescue u lol

OpenStudy (anonymous):

Lol, that's kind of creepy lol but it's cool lol

OpenStudy (anonymous):

This one is marked incorrect...

ganeshie8 (ganeshie8):

oh, take a snapshot of question and attach

OpenStudy (anonymous):

ok...hold on

ganeshie8 (ganeshie8):

kk

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

Ahh, there was a mismatch in the questions between ur snapshot and the one u posted here

ganeshie8 (ganeshie8):

the snapshot has \(\large (a+1)\) on bottom of both fractions,

ganeshie8 (ganeshie8):

but the question u typed here has : \(\huge \dfrac{ \dfrac{ \frac{ 1 }{ a+1 } +2}{ 1 } }{\color{red}{ a+7} } +7 \)

ganeshie8 (ganeshie8):

they're not same :/

OpenStudy (anonymous):

Ooooooooooh, I see it ! Ooooops 😣

ganeshie8 (ganeshie8):

Yes !

OpenStudy (anonymous):

So, how do we solve this one?

OpenStudy (anonymous):

Thank you !

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