Question

Simplify the complex fraction:

(Problem in comments...)

Answer 1

\[\frac{ \frac{ \frac{ 2 }{ x-5 } }{ x+1 } }{ x^2-25 }\]

Answer 2

\[\frac{ 2 (x-5) }{ x-5 (x-5) }\] right?

Answer 3

\[\frac{ x+1 }{ (x+5)(x-5) }\]

Answer 4

\(\huge \frac{ \frac{ \frac{ 2 }{ x-5 } }{ x+1 } }{ x^2-25 } \)

Answer 5

flip the denominator and change it to a multiplicaiton

Answer 6

\(\huge \frac{ \frac{ \frac{ 2 }{ x-5 } }{ x+1 } }{ x^2-25 } \)


is same as :

\(\huge \frac{ 2 }{ x-5 } \times \frac{x^2-25}{x+1} \)

Answer 7

factor the numerator x^2-25 now

Answer 8

(x+5)(x-5)

Answer 9

yes !

Answer 10

\(\huge \frac{ 2 }{ x-5 } \times \frac{x^2-25}{x+1} \)



\(\huge \frac{ 2 }{ x-5 } \times \frac{(x+5)(x-5)}{x+1} \)

Answer 11

cancel out (x-5) on both top and bottom

Answer 12

what do u get ?

Answer 13

2*x+5/x+1

Answer 14

\(\huge \frac{ 2 }{ x-5 } \times \frac{(x+5)(x-5)}{x+1} \)



canceling (x-5) gives


\(\huge \dfrac{2(x+5)}{x+1}\)

Answer 15

we're done.

Answer 16

Yaaaaaay! lol I'm sleepy now lol Thank you, goodnight.

Answer 17

you deserve good sleep girly :) good night !!