Question

Please help me out. :)

Solve:
lim tan 2x / tan x
x approaches 0

Answer 1

The answer given by the calculator is 2

Answer 2

how to solve?

Answer 3

\[\frac{ \tan2x }{ tanx }=\frac{ \frac{ 2tanx }{ 1=\tan^{2}x } }{ tanx }=\frac{ 2tanx }{ tanx(1-\tan^{2}x }=\frac{ 2 }{ 1-\tan^{2}x }\]
\[\lim_{x \rightarrow 0}\frac{ 2 }{ 1-\tan^{2}x }=\frac{ 2 }{ 1 }=2\]

Answer 4

\[\tan2x=\frac{ 2tanx }{ 1-\tan^{2}x }\]

Answer 5

wow man smart :P

Answer 6

:P

Answer 7

Wow! Thank you. :) ^_^