If $\int_{2}^{7} (6 f(x) + 7) \, dx = 11$, then
$\int_{2}^{7} f(x) dx =$

Question

If $\int_{2}^{7} (6 f(x) + 7) \, dx = 11$, then 
$\int_{2}^{7} f(x) dx =$

anonymous · Answer

nobody knows?

anonymous · Answer

i am trying @Jgeurts

anonymous · Answer

thanks!

anonymous · Answer

my first answer came out to 11/6 but that was wrong

anonymous · Answer

studying for a midterm so an answer i can reverse engineer into understanding it would be fantastic :p

ganeshie8 · Answer

$\large    \int \limits_{2}^{7} (6 f(x) + 7) \, dx = 11$


$\large    \int \limits_{2}^{7} 6 f(x) dx +     \int \limits_{2}^{7}  7 \, dx = 11$

$\large    6\int \limits_{2}^{7} f(x) dx +     7(7-2)  = 11$

$\large    6\int \limits_{2}^{7} f(x) dx   = -24 $

$\large    \int \limits_{2}^{7} f(x) dx   = ?$

anonymous · Answer

suddenly, its so easy, thank you so much, -4

ganeshie8 · Answer

np :)