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Mathematics 22 Online
OpenStudy (anonymous):

A coin is slightly bent, and as a result the probability of a head is 0.52. Suppose that you toss the coin four times. Use the Binomial formula to find the probability of 3 or more heads

OpenStudy (amistre64):

1 - P(0)+P(1)+P(2)

OpenStudy (amistre64):

the Ps in my head are all one term ... so i spose they should technically be wrapped in ( )

OpenStudy (anonymous):

Can anyone help with the binomial question. I think I have the correct answer but need to fully understand

OpenStudy (amistre64):

the hard part is not that hard ... its just using the binomial formula. What do you have as the binomial formula?

OpenStudy (amistre64):

i spose P(3)+P(4) is simpler to assess, less Ps. I was thinking this was a lot more trials for some reason

OpenStudy (amistre64):

\[\binom{4}{3}p^3q^1+\binom{4}{4}p^4q^0\] such that p is a success and q is (1-p), a failure

OpenStudy (anonymous):

Yes, that's what i have i ended up with 4/16 which is .25

OpenStudy (amistre64):

rechk your mathing ... 4/3 = 4, and 4/4 = 1 are the most common errors http://www.wolframalpha.com/input/?i=%5Cbinom%7B4%7D%7B3%7D%28.52%29%5E3%281-.52%29%5E1%2B%5Cbinom%7B4%7D%7B4%7D%28.52%29%5E4%281-.52%29%5E0

OpenStudy (amistre64):

that and getting the probabilities mixed up ...

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