Question

Object A has a positive charge of 4.3 uC while Object B has a positive charge of 3.6 uC and the force between them is 270N. Calculate the distance between these charges.

Answer 1

\[F = \frac{ kQq }{ r ^{2} }\]
so
\[r = \sqrt{\frac{ kQq }{ F }} = \sqrt{\frac{ (9*10^{9})*(4.3*10^{-6})*(3.6*10^{-6}) }{ 270 }} = 0.0227m = 22.7mm\]

Answer 2

\[= 0.0227m = 22.7mm\]

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