Question

The present cost of a car is $9,000. The cost of the car depreciates at the rate of $1000 per year

Answer 1

Write a function to show the cost of the car f(t) after t years
i put :f(x) = 1000(x) - 9000

Answer 2

@johnweldon1993

Answer 3

Not quite...see the constant would be the cost of the car...and that would be 9000 ....that would be added to the function...

the value DEPRECIATES at a rate of 1000 per year...that would be our variable and it would be negative.

f(x) = -1000x + 9000

Answer 4

The question then states to show what the function would be after 't' years...

"that means replacing our 'x' with 't' ...

so

f(t) = -1000t + 9000

Answer 5

Part B: What is the total cost of the car after 3 years? (4 points)

Part C: If the cost of the car was $500 less than the present cost, what would be the cost of the car after 5 years? (2 points)

Answer 6

Alright so part B

would just be replacing 't' with (3)

so

f(3) = -1000(3) + 9000
f(3) = -3000 + 9000
f(3) = 6000 <---that would be the cost of the car after 3 years

Answer 7

If the car was 500 less than the present (so 9000 - 500 = 8500)

what would the cost be after 5 years? so we have a new function

f(t) = -1000t + 8500

replace 't' with 5

f(5) = -1000(5) + 8500
f(5) = -5000 + 8500
f(5) = 3500

That would be our cost after 5 years if the original price was 8500 :)