Question

Given the parent functions f(x)= log2 (3x-9) and g(x)= log2 (x-3). what is f(x)*g(x)

Answer 1

Sorry I mean f(x)-g(x)

Answer 2

@johnweldon1993 is smart!!! You might want to ask him!:)

Answer 3

Is that log(base2) ?

\[\large log_2\] ?

Answer 4

Yes it is

Answer 5

Alright...so remember this rule

\[\large log_a (b) - log_a (c) =log_a(\frac{b}{c})\]
so really with your function we have

\[\large f(x) - g(x)\]
\[\large log_2 (3x - 9) - log_2 (x - 3)\]
\[\large log_2 (3x - 9) - log_2 (x - 3) \rightarrow log_2 (\frac{3x - 9}{x - 3})\]
\[\large log_2 (\frac{3x - 9}{x - 3})\]

can you solve that?

Answer 6

Hint* Factor out a '3' from the numerator

Answer 7

\[\large \log_2(\frac{3(x - 3)}{(x - 3)})\]
\[\large log_2 \frac{3\cancel{(x - 3)}}{\cancel{(x - 3)}}\]
\[\large log_2 3 = \space?\]

Answer 8

@johnweldon1993 you still there?

Answer 9

Its gonna be 3! :)