Question

PLease take a look at this:

Answer 1

@thomaster

Answer 2

@e.mccormick

Answer 3

@hartnn @Preetha

Answer 4

do you know arc length formula ?
have you tried solving this ?

Answer 5

\(\Large s = \int_{a}^{b} \sqrt { 1 + [f'(x)]^2 }\, dx\)

Answer 6

Yes @hartnn I tried that. I get \[\sqrt{1+sin ^{2}h}\] in the end

Answer 7

And dont know what to do from here:

Answer 8

let me try too
\(1+f'(x)^2 =1+ (1/4)(e^x-e^{-x})^2\)

Answer 9

how did you get hyperbolic sin ?

Answer 10

the original function is \[1/2 e ^{x} + e ^{-x}\]

Answer 11

isnt that coshx

Answer 12

yes, thats correct
since you know hyperbolic function, did you know
\(\large \cosh^2 x-\sinh^2 x = 1\)
?

Answer 13

OH thats why!

Answer 14

thank you hartnn

Answer 15

could you get the answer now ?
and welcome ^_^