What is the Length of a segment whose endpoints are (3,-2) and (7,6)?

Question

hartnn · Answer

Length of segment with end-points x1,y1 and x2,y2 is given as 
$\huge d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

muhammad_nauman_umair · Answer

u can use distance formula

anonymous · Answer

wats the actually answer

hartnn · Answer

did you try to first find it by yourself ?

anonymous · Answer

yes i didnt get  it im confused

hartnn · Answer

can you show what you have tried ?
we will try to spot if there is any error in your working :)

anonymous · Answer

3-2=1
7-6= 1

hartnn · Answer

we need to find differences in corresponding x co-ordinate
so find these instead

7-3 =...?
6- (-2) =... ?

muhammad_nauman_umair · Answer

sqrt(80)

anonymous · Answer

6-(-2)=8
7-3=4

hartnn · Answer

yes,
now plug those in the formula
$d= \sqrt{8^2 +4^2 } =... ?$

anonymous · Answer

=80

hartnn · Answer

that 80 is under square root sign, right ?
so your length is indeed $\sqrt{80}$

anonymous · Answer

the options are 
2  21
2    29
4   3
4   5 
sorry in between the spaces are square roots

hartnn · Answer

ok,
so can you factor 80 ?

anonymous · Answer

the square root of 80 is is

anonymous · Answer

16

hartnn · Answer

$80 = 16\times 5  \ \sqrt {18} = \sqrt{16}\times \sqrt5$
and you know whats the square root of 16 ?

anonymous · Answer

ok got tht now wat

hartnn · Answer

what did u get as your final answer ?

anonymous · Answer

idk can u just plz tell me the final answer

hartnn · Answer

whats the square root of 16 ?

anonymous · Answer

is it 4

hartnn · Answer

yes!
so $\sqrt {80} =4\sqrt 5$
:)

anonymous · Answer

so then wat

hartnn · Answer

4 sqrt 5 is one of your option!