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OpenStudy (anonymous):
i'll post what all I know :
OpenStudy (anonymous):
A+B=180-C
And.. We need to find - tan a/2 tan b/2 + tan b/2 tan c/2+ tan c/2 tan a/2
OpenStudy (anonymous):
@hartnn
OpenStudy (anonymous):
@phi
OpenStudy (anonymous):
@campbell_st
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OpenStudy (anonymous):
@thomaster
OpenStudy (anonymous):
@AccessDenied
OpenStudy (anonymous):
@Preetha
OpenStudy (anonymous):
@tHe_FiZiCx99
OpenStudy (anonymous):
@nincompoop
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OpenStudy (anonymous):
@Destinymasha
OpenStudy (anonymous):
@campbell_st
OpenStudy (anonymous):
@poopsiedoodle
OpenStudy (poopsiedoodle):
just a second let me do something for spanish class really quick and I'll take a look at it
OpenStudy (anonymous):
Thank you :) take your time :)
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OpenStudy (poopsiedoodle):
Hmm... So, it A+2B = 180, and A+B = 180 - C, then B must equal C.
OpenStudy (poopsiedoodle):
And if that's the case, then A+2C = 180, and A+C = 180 - C.
OpenStudy (anonymous):
Oh i'm extremely sorry, it ain't a+b+b, it's a+b+c. .. M mistake
OpenStudy (poopsiedoodle):
oh lol. Just a second then
OpenStudy (anonymous):
lol
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OpenStudy (poopsiedoodle):
A + B = 180 - C. So, I guess we're going to try to make some substitution happen here. A = 180 - C - B.
OpenStudy (poopsiedoodle):
So, 180 - C - B + B = 180 - C.
OpenStudy (poopsiedoodle):
Aaaaaaaaaaaaand that gets us nowhere, because after simplifying, we get 180 - C = 180 - C. Great.
OpenStudy (anonymous):
Haha..
OpenStudy (anonymous):
What if we convert tan in terms of sin's and cos' ?
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OpenStudy (poopsiedoodle):
In that case, it looks like I don't quite know what I'm doing here. Soooooo, @mathmale. And I dunno. Let's try that, I guess. This is a triangle we're working with here, right?
OpenStudy (anonymous):
i tried doing it that way, but it doesn't really took me anywhere.. :(
OpenStudy (anonymous):
Yep. Right.
OpenStudy (poopsiedoodle):
Any side lengths given?
OpenStudy (anonymous):
didn't *
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OpenStudy (anonymous):
Nopes. Just what i wrote in the question.
OpenStudy (poopsiedoodle):
Well dag, yo.
OpenStudy (poopsiedoodle):
Well, I dunno, it looks like 2 might be a side length, because tan(A/2) and such. When you do tangents, you divide the opposite side by the adjacent side. So, one of the sides is probs 2.
OpenStudy (anonymous):
No no .. i'm afraid that isn't the way we do it :/
Thanks for trying though! :D Thank you!
OpenStudy (poopsiedoodle):
Lel. Yeah, I'm not too good with geometry. But I tried :p And looks like we have hartnn here now :D
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hartnn (hartnn):
if A+B+C = pi
what does A/2 + B/2 equal ?
hartnn (hartnn):
i am intending to use
\(\tan (x+y)\)
formula
OpenStudy (anonymous):
told ya already - pi/2- c/2
OpenStudy (anonymous):
I tried it that way too.. but then it just looked so complicated!
hartnn (hartnn):
you mean pi/2 - c/2 ?
\(\tan (\pi/2 -C/2) = (1/\tan C/2)\)
now expand \(\large \tan (A/2+B/2)\)
using the formula, what u get ?
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hartnn (hartnn):
did u get how its 1/tan (C/2)
?
OpenStudy (anonymous):
tan[a/2]+tan[b/2]/ 1-tan a/2 tan b/2 = cot c/2 = 1/tanc/2
OpenStudy (anonymous):
@hartnn
hartnn (hartnn):
multiply tan c/2 on both sides :)
hartnn (hartnn):
now its just some re-arrangement of terms
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OpenStudy (anonymous):
@hartnn - Oh my goodness.. Man, thank you. Thank you so very much!
Thanks a ton! :)))