if tan = 5/12 and lies in quadrant 3 and cos -24/25 lies in quadrant 2 I'm confused how I begin to find sin (theta-beta)?
I'm assuming you meant to write tan(theta) = 5/12 and cos(beta) = -24/25
Or do I have those backwards?
Yes sorry that's what I meant to write
ok so if tan(theta) = 5/12, and theta lies in quadrant 3, then what are sin(theta) and cos(theta) ?
sin and cos would be negative
that is correct, are you able to find their values?
No that's where I'm confused
when dealing with trig, you often either refer to the unit circle or a right triangle
in this case, it's easier to deal with a right triangle, so let's draw that out
|dw:1398125592277:dw|
then add in the angle theta |dw:1398125618796:dw|
we are told that tan(theta) = 5/12 so what does that mean in terms of that right triangle I just drew (with the theta angle marker in there as well)?
tan is opposite over adjacent so opposite theta is 5 and underneath is 12
good, let's update the drawing with what you just told me |dw:1398125775523:dw| I also added in the labels for the sides. We don't know the hypotenuse yet, but we can find it. How?
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