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Mathematics 13 Online
OpenStudy (anonymous):

if tan = 5/12 and lies in quadrant 3 and cos -24/25 lies in quadrant 2 I'm confused how I begin to find sin (theta-beta)?

jimthompson5910 (jim_thompson5910):

I'm assuming you meant to write tan(theta) = 5/12 and cos(beta) = -24/25

jimthompson5910 (jim_thompson5910):

Or do I have those backwards?

OpenStudy (anonymous):

Yes sorry that's what I meant to write

jimthompson5910 (jim_thompson5910):

ok so if tan(theta) = 5/12, and theta lies in quadrant 3, then what are sin(theta) and cos(theta) ?

OpenStudy (anonymous):

sin and cos would be negative

jimthompson5910 (jim_thompson5910):

that is correct, are you able to find their values?

OpenStudy (anonymous):

No that's where I'm confused

jimthompson5910 (jim_thompson5910):

when dealing with trig, you often either refer to the unit circle or a right triangle

jimthompson5910 (jim_thompson5910):

in this case, it's easier to deal with a right triangle, so let's draw that out

jimthompson5910 (jim_thompson5910):

|dw:1398125592277:dw|

jimthompson5910 (jim_thompson5910):

then add in the angle theta |dw:1398125618796:dw|

jimthompson5910 (jim_thompson5910):

we are told that tan(theta) = 5/12 so what does that mean in terms of that right triangle I just drew (with the theta angle marker in there as well)?

OpenStudy (anonymous):

tan is opposite over adjacent so opposite theta is 5 and underneath is 12

jimthompson5910 (jim_thompson5910):

good, let's update the drawing with what you just told me |dw:1398125775523:dw| I also added in the labels for the sides. We don't know the hypotenuse yet, but we can find it. How?

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