Determine if 7, 8, and 13 can be the lengths of the sides of a triangle. If yes, classify the triangle. A. Yes, it is an acute triangle. B. Yes, it is an obtuse triangle. C. Yes, it is a right triangle. D. No, it cannot be a triangle.
\(\large c^2 = a^2 + b^2 - 2ab \cos (C)\) that gives : \(c^2\gt a^2 +b^2 \implies \text{obtuse}\) \(c^2\lt a^2 +b^2 \implies \text{acute}\) \(c^2= a^2 +b^2 \implies \text{right}\)
Is \(13^2 > 7^2 + 8^2\) ?
yes 169 is greater than 113
so is it B?
thats right ! but how are you sure that the given lengths indeed form a triangle ?
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they could be so small that you wont be able to join the other two sides, to close the shape, right ?
right
you need to check if the given lengths satisfy ALL below conditions : \(a+b < c\) \(b+c < a\) \(c+a< b\)
In words : `sum of any TWO sides must be greater than the third side`
Oh yeah i remember that
good :) B is correct btw ! good job !!
@ganeshie8 Thank You
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