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OpenStudy (anonymous):
Determine if 7, 8, and 13 can be the lengths of the sides of a triangle. If yes, classify the triangle.
A.
Yes, it is an acute triangle.
B.
Yes, it is an obtuse triangle.
C.
Yes, it is a right triangle.
D.
No, it cannot be a triangle.
12 years ago
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ganeshie8 (ganeshie8):
\(\large c^2 = a^2 + b^2 - 2ab \cos (C)\)
that gives :
\(c^2\gt a^2 +b^2 \implies \text{obtuse}\)
\(c^2\lt a^2 +b^2 \implies \text{acute}\)
\(c^2= a^2 +b^2 \implies \text{right}\)
12 years ago
ganeshie8 (ganeshie8):
Is \(13^2 > 7^2 + 8^2\) ?
12 years ago
OpenStudy (anonymous):
yes 169 is greater than 113
12 years ago
OpenStudy (anonymous):
so is it B?
12 years ago
ganeshie8 (ganeshie8):
thats right !
but how are you sure that the given lengths indeed form a triangle ?
12 years ago
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ganeshie8 (ganeshie8):
|dw:1398143794541:dw|
12 years ago
ganeshie8 (ganeshie8):
they could be so small that you wont be able to join the other two sides, to close the shape, right ?
12 years ago
OpenStudy (anonymous):
right
12 years ago
ganeshie8 (ganeshie8):
you need to check if the given lengths satisfy ALL below conditions :
\(a+b < c\)
\(b+c < a\)
\(c+a< b\)
12 years ago
ganeshie8 (ganeshie8):
In words : `sum of any TWO sides must be greater than the third side`
12 years ago
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OpenStudy (anonymous):
Oh yeah i remember that
12 years ago
ganeshie8 (ganeshie8):
good :) B is correct btw ! good job !!
12 years ago
OpenStudy (anonymous):
@ganeshie8 Thank You
12 years ago
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