Solve the following equation. Be sure to check the answer in the original equation if you multiply both sides by an expression that contains the variable. (Problem in comments...)
\[\frac{ 15 }{ x^2-9 } +\frac{ 3 }{ x+3 } =\frac{ 2 }{ x-3 }\]
@ganeshie8
Multiply all sides by \(x^2-9\).
Notice that \(x^2-9=(x-3)(x+3)\).
So we get \[ 15 + 3(x-3) = 2(x+3) \]
That's the answer?
you need to simplify and solve for \(x\), but the problem is much simpler now.
is it, 15+3x+9=2x+6?
\(15 + 3(x-3) = 2(x+3) \) becomes \(15 + 3x \color{red}{-} 9= 2x+6 \) right ?
after that, you need to solve \(x\), which is same as isolating \(x\)
Thats when i factor right?
I am having some trouble with this... Did you work out the answer @cookiibabii93 Did you get x to be 0, because thats what i got...
You should get \(x=0\).
@wio I kind of get scared when x=0 because I always expect x to never be 0.
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