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OpenStudy (anonymous):
Solve the following equation. Be sure to check the answer in the original equation if you multiply both sides by an expression that contains the variable.
(Problem in comments...)
12 years ago
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OpenStudy (anonymous):
\[\frac{ 15 }{ x^2-9 } +\frac{ 3 }{ x+3 } =\frac{ 2 }{ x-3 }\]
12 years ago
OpenStudy (anonymous):
@ganeshie8
12 years ago
OpenStudy (anonymous):
Multiply all sides by \(x^2-9\).
12 years ago
OpenStudy (anonymous):
Notice that \(x^2-9=(x-3)(x+3)\).
12 years ago
OpenStudy (anonymous):
So we get \[
15 + 3(x-3) = 2(x+3)
\]
12 years ago
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OpenStudy (anonymous):
That's the answer?
12 years ago
OpenStudy (anonymous):
you need to simplify and solve for \(x\), but the problem is much simpler now.
12 years ago
OpenStudy (anonymous):
is it, 15+3x+9=2x+6?
12 years ago
ganeshie8 (ganeshie8):
\(15 + 3(x-3) = 2(x+3) \)
becomes
\(15 + 3x \color{red}{-} 9= 2x+6 \)
right ?
12 years ago
ganeshie8 (ganeshie8):
after that, you need to solve \(x\), which is same as isolating \(x\)
12 years ago
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OpenStudy (anonymous):
Thats when i factor right?
12 years ago
OpenStudy (anonymous):
I am having some trouble with this... Did you work out the answer @cookiibabii93
Did you get x to be 0, because thats what i got...
12 years ago
OpenStudy (anonymous):
You should get \(x=0\).
12 years ago
OpenStudy (anonymous):
@wio
I kind of get scared when x=0 because I always expect x to never be 0.
12 years ago
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