\[\lim_{x \rightarrow 0} (\frac{ (1+x)^\frac{ 1 }{ x } }{ e })^\frac{ 1 }{ x }\]
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OpenStudy (anonymous):
@AravindG
Mr. Admin please give me solution not *answer* !!
OpenStudy (anonymous):
@AravindG ?
OpenStudy (anonymous):
@hartnn ?? @ganeshie8 ??
OpenStudy (anonymous):
@zepdrix ?? @Hero ??
OpenStudy (anonymous):
@AravindG ?
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OpenStudy (anonymous):
@thomaster ?
OpenStudy (anonymous):
@beccaboo333 ?? @Luigi0210 ??
hartnn (hartnn):
let that limit be = L
then take log on both sides and simplify the right side using log rules.
OpenStudy (anonymous):
u mean like
log L=\[\frac{ 1 }{ x }(\log \lim_{x \rightarrow 0} (1+x)^\frac{ 1 }{ x }-\log \lim_{x \rightarrow 0} x)\]
OpenStudy (anonymous):
@hartnn ?
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OpenStudy (anonymous):
@hartnn ??
OpenStudy (anonymous):
@Hero ?? @ganeshie8 ??
hartnn (hartnn):
sorry for late replies, my internet connection is very slow,
don't you have a standard result for limit x \(\to 0 \) of log (1+x)^(1/x)
?
if not, which standard limit formulas can you use ?
OpenStudy (anonymous):
the simplification i made isnt correct?
OpenStudy (anonymous):
can u simplify please!
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OpenStudy (anonymous):
@hartnn ?
hartnn (hartnn):
\(\large \ln L = \lim \limits_{x\to0} (1/x) [\ln (1+x)^{(1/x)}-\ln e]\)
OpenStudy (anonymous):
lne=1
OpenStudy (anonymous):
@hartnn ?? now?
OpenStudy (anonymous):
@hartnn ?
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