Question

I NEED HELP!! PLZ! WILL GIVE MEDAL AND FAN!!!

solve the equation. check the solution
4=√p-2
A.√6
B.36
C.3
D.6

solve the quation identify any extraneous solutions.
8√9j+10=1
A.9/64 is a solution of the original equation. -9/64 is the ES
B.9/64 is the solution of the original equation
C.-9/64 is the solution of the original equation. 9/64 is an ES
D.there is no solution

Answer 1

\[4=\sqrt{p}-2\]

\[4+2=\sqrt{p}\]

\[6=\sqrt{p}\]

\[6^2=(\sqrt{p})^2\]

\[\boxed{\boxed{p=36}}\]

____________________________________________________________________

\[8*\sqrt{9j}+10=1\]

\[8*\sqrt{9j}=1-10\]

\[8*\sqrt{9j}=-9\]

\[8*3\sqrt{j}=-9\]

\[8\sqrt{j}=-3\]

\[\sqrt{j}=-\frac{3}{8}\]

\[(\sqrt{j})^2=\left(-\frac{3}{8}\right)^2\]

\[\boxed{\boxed{j=\frac{9}{64}}}\]

Answer 2

so for the second one would it be A orB?

Answer 3

@D3xt3R

Answer 4

B

Answer 5

can you help me with a few more?

Answer 6

what is the domain of the function?
y=√4x-4
A.x>-1
B. x> or = to 1
C.x> or equal to -1
D.x> or equal to

Answer 7

@D3xt3R

Answer 8

the function 4x-4 never can be negative then:

\[y=\sqrt{4x-4}\]

\[4x-4\geq0\]

\[\boxed{\boxed{x\geq1}}\]

Answer 9

ok thanks. what about this one
what is the cos for for the triangle shown
A.4/3
B.4/5
C.5/4
D.3/5

Answer 10

@D3xt3R

Answer 11

please help! I will give u plenty of medals lol

Answer 12

I have a test now, when I'll back i answer