Question

Find the extreme values of the function and where they occur. y=x^3-12x+2

Answer 1

Do you mean the maximum?

Answer 2

the maximum is -2

Answer 3

I need both max and min!

Answer 4

x=2

Answer 5

To find the extreme values we have to derivate this function

\[y=x^3-12x+2\]

\[y'=3x^2-12\]

\[y'=0\]

\[3x^2-12=0\]

\[\boxed{\boxed{x_1=2~~and~~x_2=-2}}\]

the second derivate will show us when it occur

\[y''=6x\]

\[\therefore-2~is~the~minimun~global~and~2~is~the~maximum~global\]

Answer 6

so you're max is -2 and your min is 2

Answer 7

Thanks for the help!

Answer 8

you're welcome :)