Question

2 Sin[θ/2] == 1

Answer 1

Dividing both side by 2 we get \[\sin(\theta/2) = 1/2\]
Now applying inverse function of sin on both side we get
\[\theta/2 = \sin^{-1} (1/2) \]

Answer 2

\[\sin^{-1} (1/2) = \Pi/6\]
so we get \[\theta/2 = \Pi/6
this gives you
\theta = \Pi/12\]
I hope this will help you :)

Answer 3

thank you so much