Please help I need to finish this today or I'm grounded and I will not graduate! :()
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OpenStudy (anonymous):
OpenStudy (anonymous):
hero (hero):
Standard form of a linear equation is
Ax + By = C
hero (hero):
You have
\(x + \dfrac{4y}{7} + 2 = 0\)
Start by doing this:
1. Subtract 2 from both sides
2. Multiply both sides by 7
OpenStudy (anonymous):
\[x+4y=14\]
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OpenStudy (anonymous):
\[7x+4y=14\]
OpenStudy (anonymous):
?
OpenStudy (anonymous):
@Hero which one would it be?
OpenStudy (anonymous):
@suyogsomavanshi
OpenStudy (anonymous):
General form of linear equation is Ax + by = c
We are having x +( 4y /7) + 2 = 0
So we have to first get rid of 2 from left hand side can you try for it ?
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OpenStudy (anonymous):
\[x+(4/7)=-2\]
OpenStudy (anonymous):
Correct but there is y with (4/7) right ???
So we get x + 4y / 7 = -2
Now we need to get rid of 7 from bottom of 4y Any idea ??
hero (hero):
If you multiplied both sides by 7 you should have gotten
7x + 4y = -14
OpenStudy (anonymous):
ok so time both sides by 7
OpenStudy (anonymous):
correct getting this ????
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hero (hero):
You had it, but you forgot the negative in front of the 14
OpenStudy (anonymous):
so 7x+4y=-14 ok I didn't have the -2 before thanks and what about the first attachment
OpenStudy (anonymous):
So this would be in our desired form like Ax+By= c
7x+4y=-14 Is it clear to you ?
OpenStudy (anonymous):
yes it is thanks!
OpenStudy (anonymous):
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OpenStudy (anonymous):
Any doubt ???
OpenStudy (anonymous):
I don't even know where to begin on the question I just uploaded?
OpenStudy (anonymous):
@acxbox22 @mathmale
OpenStudy (anonymous):
@suyogsomavanshi
OpenStudy (anonymous):
\[\left[\begin{matrix}4 & 7 \\ 1 & 2\end{matrix}\right]*\left(\begin{matrix}24 \\ 7\end{matrix}\right)\]
i also need help with this
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hero (hero):
@Erob, post it as a separate question. Close this question and post a new one.
OpenStudy (anonymous):
First we would try to fix first one
OpenStudy (anonymous):
We have to consider two odd numbers as 2n + 1 and 2n + 3 getting this ?
OpenStudy (anonymous):
Hello ... ???
OpenStudy (anonymous):
I'll post the third one seperae and k
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OpenStudy (anonymous):
2n+1 and 2n+3 got it
OpenStudy (anonymous):
@suyogsomavanshi
OpenStudy (anonymous):
Now sum of them is = 2n + 1 + 2n + 3 = ---- ?
OpenStudy (anonymous):
4n+4
OpenStudy (anonymous):
perfect
Now it says there sum is increased by 15 so how you could write it ??
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